Let’s go through the questions one by one:
Question 21
The confidence interval for the mean price of a gallon of propane in Georgia is $2.60 to $2.78. To determine which statement should be disputed, we consider values outside the confidence interval:
- The mean price for a gallon of propane in Georgia is $2.75 → This value is inside the interval (disputed).
- The mean price for a gallon of propane in Georgia is $2.62 → This value is inside the interval (not disputed).
- The mean price for a gallon of propane in Georgia is $2.69 → This value is inside the interval (not disputed).
- The mean price for a gallon of propane in Georgia is $2.85 → This value is outside the interval (this value should be disputed).
Answer: The mean price for a gallon of propane in the state of Georgia is $2.85.
Question 22
Without the scatterplot, it’s impossible to determine the association. However, to choose the correct option, you might consider the general characteristics of scatterplots:
- If points tend to rise together from left to right, it's positive and linear.
- If points rise but curve up, it's positive and non-linear.
- If points tend to fall together, it's negative and linear.
- If points fall but curve down, it's negative and non-linear.
Without seeing the scatterplot, I cannot provide a final answer. Please evaluate the scatterplot with these descriptions.
Question 23
When the p-value from a hypothesis test is very small (less than the level of significance), it suggests strong evidence against the null hypothesis. This means we have evidence that supports the alternative hypothesis.
Answer: there is strong evidence to claim the alternative hypothesis appears to be true.
Question 24
To calculate the p-value for the given hypotheses \( H_0: p = 0.40 \) and \( H_a: p > 0.40 \).
The sample proportion \( \hat{p} = \frac{168}{400} = 0.42 \).
Using the standard formula for the z-test:
- Compute the standard error (SE): \[ SE = \sqrt{\frac{p_0(1 - p_0)}{n}} = \sqrt{\frac{0.40(0.60)}{400}} = \sqrt{\frac{0.24}{400}} = \sqrt{0.0006} \approx 0.02449 \]
- Compute the z-score: \[ z = \frac{\hat{p} - p_0}{SE} = \frac{0.42 - 0.40}{0.02449} \approx \frac{0.02}{0.02449} \approx 0.817 \]
- Determine the p-value from the z-score associated with the standard normal distribution.
Using a z-table, the p-value corresponding to \( z = 0.817 \) is approximately 0.207.
Answer: 0.207
Question 25
With a p-value of 0.17 and a significance level of 0.05, since the p-value is greater than the level of significance, we fail to reject the null hypothesis.
Answer: fail to reject the null hypothesis.