To use the substitution method to solve the given system of equations, we can start with the first equation:
- \(2x + 3y = 4\)
From this equation, we can solve for one variable in terms of the other. Let's solve for \(y\):
\[ 3y = 4 - 2x \] \[ y = \frac{4 - 2x}{3} \]
Now we substitute \(y\) into the second equation:
- \(-4x - 6y = -8\)
Substituting \(y\) gives us:
\[ -4x - 6\left(\frac{4 - 2x}{3}\right) = -8 \]
Now we simplify this equation:
\[ -4x - \frac{6(4 - 2x)}{3} = -8 \]
Calculate \(6(4 - 2x)\):
\[ 6(4) - 6(2x) = 24 - 12x \]
Putting it back into the equation:
\[ -4x - \frac{24 - 12x}{3} = -8 \]
Now let's break down the fraction:
\[ -4x - 8 + 4x = -8 \]
Combine like terms:
\[ -8 = -8 \]
This is a true statement indicating that both equations are actually dependent (the second equation is just a multiple of the first). This means that we have infinitely many solutions.
Thus, the system has infinite solutions.
In conclusion, the correct response is:
infinite solutions.