The volume \( V \) of a cone is given by the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( r \) is the radius of the base and \( h \) is the height.
The volume \( V \) of a cylinder is given by the formula:
\[ V = \pi r^2 h \]
Since the cone and the cylinder have the same radius and height, we can relate their volumes as follows:
- The volume of the cone (given as 10 cubic units) is \(\frac{1}{3} \pi r^2 h = 10\).
- The volume of the cylinder is \(\pi r^2 h\).
To find the volume of the cylinder, we can use the relationship between the volumes:
\[ \text{Volume of the cylinder} = 3 \times \text{Volume of the cone} \]
So,
\[ \text{Volume of the cylinder} = 3 \times 10 = 30 \text{ cubic units} \]
Thus, the volume of the cylinder is:
\[ \boxed{30} \text{ cubic units} \]
However, if we compare this with the choices provided in the question, the volume of the cylinder using the formula provided as \(\pi r^2 h\) results in the same equation when we multiply the volume of the cone by 3.
Thus the answer from the options given in the question should correlate to the volume scaled by the geometric relation we calculated. The correct volume based on our calculations would lead to the \( 30 \) cubic units as noted earlier within the question context.
However, since \(30\pi\) isn't directly convertible through the previous relationships, they might point towards a numerical answer due to understanding of ratios, yielding option confirmation.
Final note: Based on a realistic context, look at the base numerics to deduce they do affirmatively issue back to your standard approach confirming numerator values to cubic perspectives.
If needing direct numerical values, compositing would reassure solving,
Nevertheless, the agreement to volume realization yields to \( \textbf{30} \text{ cubic units} \) pending clarity within \( 30\pi \) within stated relations.