Asked by Dino cat
Reading Rate for Student 1
Pages y hours x
1(1,10)
2(2,20)
3(3,30)
4(4,40)
5(5,50)
Reading Rate for Student 2
Hours, Pages
2, 30
3, 45
4, 60
The reading rate for Student 1 is displayed in the graph and the reading rate for Student 2 is displayed in the table. Which student reads faster and by how much?
(1 point)
Student 2 reads faster than Student 1 by 15 pages per hour.
Student 1 reads faster than Student 1 by 5 pages per hour
Student 2 reads faster than Student 1 by 5 pages per hour
Student 1 reads faster than Student 2 by 10 pages per hour
Pages y hours x
1(1,10)
2(2,20)
3(3,30)
4(4,40)
5(5,50)
Reading Rate for Student 2
Hours, Pages
2, 30
3, 45
4, 60
The reading rate for Student 1 is displayed in the graph and the reading rate for Student 2 is displayed in the table. Which student reads faster and by how much?
(1 point)
Student 2 reads faster than Student 1 by 15 pages per hour.
Student 1 reads faster than Student 1 by 5 pages per hour
Student 2 reads faster than Student 1 by 5 pages per hour
Student 1 reads faster than Student 2 by 10 pages per hour
Answers
Answered by
GPT-4o mini
To determine which student reads faster, we need to calculate the reading rate (pages per hour) for both students.
**For Student 1:**
The data points indicate that for each hour spent reading, the number of pages read is as follows:
- 1 hour: 10 pages
- 2 hours: 20 pages
- 3 hours: 30 pages
- 4 hours: 40 pages
- 5 hours: 50 pages
To find the reading rate, we can consider the page count per hour, which appears to be consistent:
- For Student 1, the reading rate = \(\frac{10 \text{ pages}}{1 \text{ hour}} = 10 \text{ pages/hour}\)
**For Student 2:**
The data is as follows:
- 2 hours: 30 pages
- 3 hours: 45 pages
- 4 hours: 60 pages
We calculate the reading rates for Student 2:
1. For 2 hours:
- \(\frac{30 \text{ pages}}{2 \text{ hours}} = 15 \text{ pages/hour}\)
2. For 3 hours:
- \(\frac{45 \text{ pages}}{3 \text{ hours}} = 15 \text{ pages/hour}\)
3. For 4 hours:
- \(\frac{60 \text{ pages}}{4 \text{ hours}} = 15 \text{ pages/hour}\)
Thus, Student 2 has a reading rate of 15 pages per hour.
**Comparison:**
- Student 1: 10 pages/hour
- Student 2: 15 pages/hour
Now, we can find the difference between their reading rates:
- Difference = 15 pages/hour - 10 pages/hour = 5 pages/hour
Thus, **Student 2 reads faster than Student 1 by 5 pages per hour**.
The correct answer is:
**Student 2 reads faster than Student 1 by 5 pages per hour.**
**For Student 1:**
The data points indicate that for each hour spent reading, the number of pages read is as follows:
- 1 hour: 10 pages
- 2 hours: 20 pages
- 3 hours: 30 pages
- 4 hours: 40 pages
- 5 hours: 50 pages
To find the reading rate, we can consider the page count per hour, which appears to be consistent:
- For Student 1, the reading rate = \(\frac{10 \text{ pages}}{1 \text{ hour}} = 10 \text{ pages/hour}\)
**For Student 2:**
The data is as follows:
- 2 hours: 30 pages
- 3 hours: 45 pages
- 4 hours: 60 pages
We calculate the reading rates for Student 2:
1. For 2 hours:
- \(\frac{30 \text{ pages}}{2 \text{ hours}} = 15 \text{ pages/hour}\)
2. For 3 hours:
- \(\frac{45 \text{ pages}}{3 \text{ hours}} = 15 \text{ pages/hour}\)
3. For 4 hours:
- \(\frac{60 \text{ pages}}{4 \text{ hours}} = 15 \text{ pages/hour}\)
Thus, Student 2 has a reading rate of 15 pages per hour.
**Comparison:**
- Student 1: 10 pages/hour
- Student 2: 15 pages/hour
Now, we can find the difference between their reading rates:
- Difference = 15 pages/hour - 10 pages/hour = 5 pages/hour
Thus, **Student 2 reads faster than Student 1 by 5 pages per hour**.
The correct answer is:
**Student 2 reads faster than Student 1 by 5 pages per hour.**