To classify the sequence \( { a_n } = { 3, -1, \frac{1}{3}, -\frac{1}{9}, \ldots } \), we need to determine if it is arithmetic, geometric, or neither.
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Arithmetic Sequence: A sequence is arithmetic if the difference between consecutive terms is constant. Let's calculate the differences:
- \( -1 - 3 = -4 \)
- \( \frac{1}{3} - (-1) = \frac{1}{3} + 1 = \frac{4}{3} \)
- \( -\frac{1}{9} - \frac{1}{3} = -\frac{1}{9} - \frac{3}{9} = -\frac{4}{9} \)
The differences are -4, \( \frac{4}{3} \), and \( -\frac{4}{9} \), which are not constant. Therefore, it is not an arithmetic sequence.
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Geometric Sequence: A sequence is geometric if the ratio between consecutive terms is constant. Let's calculate the ratios:
- \( \frac{-1}{3} \)
- \( \frac{\frac{1}{3}}{-1} = -\frac{1}{3} \)
- \( \frac{-\frac{1}{9}}{\frac{1}{3}} = -\frac{1}{9} \times \frac{3}{1} = -\frac{1}{3} \)
The ratios \( \frac{-1}{3} \), and \( \frac{-1}{3} \), and \( \frac{-1}{3} \) are constant.
Since the sequence has a constant ratio, it is classified as a geometric sequence.
The answer is: geometric