Asked by Jaz
Find the first term of the arithmetic sequence in which a subscript 27 baseline equals negative Start Fraction 1 over 2 End Fraction and the common difference is 2.
(1 point)
Responses
Start Fraction 103 over 2 End Fraction
Image with alt text: Start Fraction 103 over 2 End Fraction
negative Start Fraction 105 over 2 End Fraction
Image with alt text: negative Start Fraction 105 over 2 End Fraction
negative Start Fraction 103 over 2 End Fraction
Image with alt text: negative Start Fraction 103 over 2 End Fraction
Start Fraction 111 over 2 End Fraction
(1 point)
Responses
Start Fraction 103 over 2 End Fraction
Image with alt text: Start Fraction 103 over 2 End Fraction
negative Start Fraction 105 over 2 End Fraction
Image with alt text: negative Start Fraction 105 over 2 End Fraction
negative Start Fraction 103 over 2 End Fraction
Image with alt text: negative Start Fraction 103 over 2 End Fraction
Start Fraction 111 over 2 End Fraction
Answers
Answered by
GPT-4o mini
To find the first term of the arithmetic sequence given \( a_{27} = -\frac{1}{2} \) and the common difference \( d = 2 \), we can use the formula for the \( n \)-th term of an arithmetic sequence:
\[
a_n = a_1 + (n - 1)d
\]
Where:
- \( a_n \) is the \( n \)-th term,
- \( a_1 \) is the first term,
- \( d \) is the common difference,
- \( n \) is the term number.
Given:
- \( n = 27 \)
- \( a_{27} = -\frac{1}{2} \)
- \( d = 2 \)
We can substitute these values into the formula:
\[
-\frac{1}{2} = a_1 + (27 - 1) \cdot 2
\]
This simplifies to:
\[
-\frac{1}{2} = a_1 + 26 \cdot 2
\]
\[
-\frac{1}{2} = a_1 + 52
\]
Now, to isolate \( a_1 \), subtract 52 from both sides:
\[
a_1 = -\frac{1}{2} - 52
\]
We can convert \( 52 \) to a fraction with a denominator of 2:
\[
52 = \frac{104}{2}
\]
\[
a_1 = -\frac{1}{2} - \frac{104}{2} = -\frac{1 + 104}{2} = -\frac{105}{2}
\]
Thus, the first term \( a_1 \) is:
\[
\boxed{-\frac{105}{2}}
\]
\[
a_n = a_1 + (n - 1)d
\]
Where:
- \( a_n \) is the \( n \)-th term,
- \( a_1 \) is the first term,
- \( d \) is the common difference,
- \( n \) is the term number.
Given:
- \( n = 27 \)
- \( a_{27} = -\frac{1}{2} \)
- \( d = 2 \)
We can substitute these values into the formula:
\[
-\frac{1}{2} = a_1 + (27 - 1) \cdot 2
\]
This simplifies to:
\[
-\frac{1}{2} = a_1 + 26 \cdot 2
\]
\[
-\frac{1}{2} = a_1 + 52
\]
Now, to isolate \( a_1 \), subtract 52 from both sides:
\[
a_1 = -\frac{1}{2} - 52
\]
We can convert \( 52 \) to a fraction with a denominator of 2:
\[
52 = \frac{104}{2}
\]
\[
a_1 = -\frac{1}{2} - \frac{104}{2} = -\frac{1 + 104}{2} = -\frac{105}{2}
\]
Thus, the first term \( a_1 \) is:
\[
\boxed{-\frac{105}{2}}
\]
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