To determine which of the given points could be found in the table of values for the function \( g(x) = \cos(-1.5x) - 1 \), we can evaluate the function at \( x = \frac{2\pi}{3} \) and check the output.
- Calculate \( g\left(\frac{2\pi}{3}\right) \): \[ g\left(\frac{2\pi}{3}\right) = \cos\left(-1.5 \cdot \frac{2\pi}{3}\right) - 1 \] Simplifying the argument: \[ -1.5 \cdot \frac{2\pi}{3} = -\pi \] Now, evaluate \( \cos(-\pi) \): \[ \cos(-\pi) = -1 \] Thus, \[ g\left(\frac{2\pi}{3}\right) = -1 - 1 = -2 \]
From the calculations, we find:
- \( g\left(\frac{2\pi}{3}\right) = -2 \)
Now we can look at the provided options:
- \( \left(\frac{2\pi}{3}, 0\right) \)
- "There is no viable option provided."
- \( \left(\frac{2\pi}{3}, -1\right) \)
- \( \left(\frac{2\pi}{3}, -2\right) \)
The only point that matches our result is:
- \( \left(\frac{2\pi}{3}, -2\right) \)
So, the correct response is \( \left(\frac{2\pi}{3}, -2\right) \).