To solve the expression \( 2(k-4) - 3(2k-1) \), we'll first distribute the numbers outside the parentheses and then combine like terms.
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Distribute \( 2 \) and \( -3 \): \[ 2(k-4) = 2k - 8 \] \[ -3(2k-1) = -6k + 3 \]
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Now combine these results: \[ 2k - 8 - 6k + 3 \]
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Combine like terms: \[ (2k - 6k) + (-8 + 3) = -4k - 5 \]
So the final result is: \[ \boxed{-4k - 5} \]