In guinea pigs, rough coats (with lots of swirly cowlicks) are dominant over smooth coats. If a male homozygous dominant guinea pig is crossed with a female heterozygous guinea pig, what are the possible genotypes and phenotypes of the offspring? Complete the Punnett square and the percentages of rough and smooth coated offspring.

Question

***Please follow all Punnett square rules to complete this question. (Letters and numbers, only)

Please use the following: Rough = R and Smooth = r


offspring 1 offspring 2
offspring 3 offspring 4

% rough

% smooth



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Answer 1

To solve this problem, we need to set up a Punnett square based on the genotypes of the parent guinea pigs.

The male guinea pig is homozygous dominant for rough coats (RR), and the female is heterozygous (Rr).

Here's the Punnett square setup:

| | R | R | |---------|------|------| | R | RR | RR | | r | Rr | Rr |

Now, let's fill in the squares:

• Offspring 1: RR
• Offspring 2: RR
• Offspring 3: Rr
• Offspring 4: Rr

Now, let's summarize the genotypes and phenotypes:

Genotypes:

• Offspring 1: RR
• Offspring 2: RR
• Offspring 3: Rr
• Offspring 4: Rr

Phenotypes:

• Offspring 1: Rough
• Offspring 2: Rough
• Offspring 3: Rough
• Offspring 4: Rough

As a result, we have:

• 100% of the offspring will have rough coats.
• 0% of the offspring will have smooth coats.

Now, let's fill in the blanks:

Blank 1: RR
Blank 2: RR
Blank 3: Rr
Blank 4: Rr
Blank 5: % rough = 100%
Blank 6: % smooth = 0%
Blank 7: (Leave blank, not used in this scenario)
Blank 8: (Leave blank, not used in this scenario)
Blank 9: (Leave blank, not used in this scenario)
Blank 10: (Leave blank, not used in this scenario)

These details complete the requirement for your question.