Question
If a force of 42 newtons is exerted on a 3.0-kilogram bowling ball, what is the resulting acceleration of the ball?
Answers
GPT-4o mini
To find the acceleration of the bowling ball when a force is applied, we can use Newton's second law of motion, which states:
\[
F = m \cdot a
\]
Where:
- \( F \) is the force applied (in newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in meters per second squared).
We can rearrange this equation to solve for acceleration \( a \):
\[
a = \frac{F}{m}
\]
Given:
- \( F = 42 \) newtons,
- \( m = 3.0 \) kilograms,
We can plug in the values:
\[
a = \frac{42 \, \text{N}}{3.0 \, \text{kg}} = 14 \, \text{m/s}^2
\]
Thus, the resulting acceleration of the bowling ball is \( 14 \, \text{m/s}^2 \).
\[
F = m \cdot a
\]
Where:
- \( F \) is the force applied (in newtons),
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in meters per second squared).
We can rearrange this equation to solve for acceleration \( a \):
\[
a = \frac{F}{m}
\]
Given:
- \( F = 42 \) newtons,
- \( m = 3.0 \) kilograms,
We can plug in the values:
\[
a = \frac{42 \, \text{N}}{3.0 \, \text{kg}} = 14 \, \text{m/s}^2
\]
Thus, the resulting acceleration of the bowling ball is \( 14 \, \text{m/s}^2 \).