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Question 8;

Use the slope intercept form of the equation to evaluate the equation at x= 3 and X =11
Unit 6 Algebraic Expressions portfolio

3 answers

To evaluate an equation in slope-intercept form at specific values of \( x \), you'll first need the slope-intercept form of a linear equation, which is:

\[ y = mx + b \]

where:

  • \( m \) represents the slope,
  • \( b \) represents the y-intercept.

Once you have the specific equation, you can substitute the values of \( x \) (in your case, \( x = 3 \) and \( x = 11 \)) into the equation to find the corresponding \( y \)-values.

If you provide me with the specific values of \( m \) and \( b \) (or the complete equation), I can help you evaluate the equation at \( x = 3 \) and \( x = 11 \).

The equation is y=5+3 x2 -7 -2x2

It looks like the equation you've provided is:

\[ y = 5 + 3x^2 - 7 - 2x^2 \]

Let's simplify this equation first:

  1. Combine like terms:

\[ y = 5 - 7 + (3x^2 - 2x^2) \]

This simplifies to:

\[ y = -2 + x^2 \]

Now we have the equation in a standard polynomial form. To evaluate this at \( x = 3 \) and \( x = 11 \):

For \( x = 3 \):

\[ y = -2 + (3)^2 \] \[ y = -2 + 9 \] \[ y = 7 \]

For \( x = 11 \):

\[ y = -2 + (11)^2 \] \[ y = -2 + 121 \] \[ y = 119 \]

Summary of Evaluations:

  • At \( x = 3 \), \( y = 7 \)
  • At \( x = 11 \), \( y = 119 \)