Question

Question 8;
Use the slope intercept form of the equation to evaluate the equation at x= 3 and X =11
Unit 6 Algebraic Expressions portfolio

Answer 1

The equation is y=5+3 x2 -7 -2x2

Answer 2

To evaluate an equation in slope-intercept form at specific values of \( x \), you'll first need the slope-intercept form of a linear equation, which is:

\[
y = mx + b
\]

where:
- \( m \) represents the slope,
- \( b \) represents the y-intercept.

Once you have the specific equation, you can substitute the values of \( x \) (in your case, \( x = 3 \) and \( x = 11 \)) into the equation to find the corresponding \( y \)-values.

If you provide me with the specific values of \( m \) and \( b \) (or the complete equation), I can help you evaluate the equation at \( x = 3 \) and \( x = 11 \).

Answer 3

It looks like the equation you've provided is:

\[
y = 5 + 3x^2 - 7 - 2x^2
\]

Let's simplify this equation first:

1. Combine like terms:

\[
y = 5 - 7 + (3x^2 - 2x^2)
\]

This simplifies to:

\[
y = -2 + x^2
\]

Now we have the equation in a standard polynomial form. To evaluate this at \( x = 3 \) and \( x = 11 \):

### For \( x = 3 \):

\[
y = -2 + (3)^2
\]
\[
y = -2 + 9
\]
\[
y = 7
\]

### For \( x = 11 \):

\[
y = -2 + (11)^2
\]
\[
y = -2 + 121
\]
\[
y = 119
\]

### Summary of Evaluations:
- At \( x = 3 \), \( y = 7 \)
- At \( x = 11 \), \( y = 119 \)