Question

3x + y = 3x + y = 2 Solve the system of equations

Answer 1

The equation you've written seems to be incorrect since it has the same expression repeated. However, it appears you may want to solve the system of equations with two separate equations. Let's assume your intention is to write a system of equations like this:

1. \(3x + y = 2\)
2. (Assuming a second equation, but it's not specified; let's say) \(x - y = 1\)

To solve the system of equations, we can use either substitution or elimination. For example, let's use substitution.

**From the first equation**:
\[
y = 2 - 3x
\]

**Now substitute \(y\) into the second equation**:
\[
x - (2 - 3x) = 1
\]
\[
x - 2 + 3x = 1
\]
\[
4x - 2 = 1
\]
\[
4x = 3
\]
\[
x = \frac{3}{4}
\]

**Now substitute \(x\) back into the expression for \(y\)**:
\[
y = 2 - 3\left(\frac{3}{4}\right)
\]
\[
y = 2 - \frac{9}{4}
\]
\[
y = \frac{8}{4} - \frac{9}{4}
\]
\[
y = -\frac{1}{4}
\]

So, the solution to the system would be:
\[
x = \frac{3}{4}, \quad y = -\frac{1}{4}
\]

If you have different equations, please specify so I can help you accurately!