To determine if the graph of the function \( y = -25x + 3 \) matches the line illustrated in the given description, we can analyze the function itself.
The function is in the slope-intercept form \( y = mx + b \), where:
- \( m = -25 \) (the slope)
- \( b = 3 \) (the y-intercept)
The slope of \(-25\) indicates that for every unit increase in \( x \), \( y \) decreases by \( 25 \). This creates a very steep line descending sharply from left to right.
Next, let's evaluate the two points mentioned:
- The point \( (0, 3) \) corresponds to the y-intercept of the function, which is correct.
- At \( x = 5 \), we substitute \( x \) into the function:
\[ y = -25(5) + 3 = -125 + 3 = -122 \]
The point \( (5, 1) \) mentioned in the description does not satisfy the equation \( y = -25x + 3 \), as substituting \( x = 5 \) gives \( y = -122 \), not \( 1 \).
Since the line cannot pass through both \( (0, 3) \) and \( (5, 1) \) for the equation \( y = -25x + 3 \), we conclude that the given graph is not the graph of the function.
Thus, the answer is:
2 (no).