1. One-tailed or Two-tailed Test:
In this case, we are testing whether the proportion of professional athletes who can score a ranking of "light speed" is less than 18%. Because the alternative hypothesis \( H_1: p < 0.18 \) specifies a direction (less than), this is a one-tailed test.
2. Test Statistic:
To calculate the test statistic for a proportion Z-test, we use the formula:
\[
Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}
\]
Where:
- \(\hat{p} = \frac{x}{n}\) (the sample proportion)
- \(x\) = number of successes (in this case, athletes who scored "light speed")
- \(n\) = sample size
- \(p_0 = 0.18\) (the proportion under the null hypothesis)
From your data:
Calculate \(\hat{p}\):
\[
\hat{p} = \frac{14}{120} = 0.1167
\]
Plug into the Z-test formula:
\[
Z = \frac{0.1167 - 0.18}{\sqrt{\frac{0.18(1 - 0.18)}{120}}}
\]
\[
= \frac{0.1167 - 0.18}{\sqrt{\frac{0.18 \cdot 0.82}{120}}}
\]
\[
= \frac{0.1167 - 0.18}{\sqrt{\frac{0.1476}{120}}}
\]
\[
= \frac{0.1167 - 0.18}{\sqrt{0.001230}}
\]
\[
= \frac{-0.0633}{0.0351} \approx -1.803
\]
Rounded to three decimal places, the test statistic is:
\[
Z \approx -1.803
\]
3. P-value:
To find the p-value for the test statistic \( Z = -1.803 \), we can look it up in the standard normal distribution table or use a calculator.
Using a Z-table or calculator:
- The p-value corresponds to the area to the left of \( Z \) since this is a one-tailed test.
For \( Z = -1.803 \):
- The p-value is approximately \( 0.0356 \).
Rounded to three decimal places, the p-value is:
\[
\text{p-value} \approx 0.036
\]
Summary:
- Test Statistic (Z): -1.803
- P-value: 0.036
If you compare this p-value with your significance level (0.10), you can make a decision on the null hypothesis. Since \( 0.036 < 0.10 \), you would reject the null hypothesis in favor of the alternative.