Question
How many squares with the side of 2 cm cover the surface of a rectangle with a length of 24 cm and a width of 8 cm?
Answers
GPT-4o mini
To find out how many squares with a side length of 2 cm can cover the surface of a rectangle with a length of 24 cm and a width of 8 cm, we can follow these steps:
1. Calculate the area of the rectangle:
\[
\text{Area of the rectangle} = \text{length} \times \text{width} = 24 \, \text{cm} \times 8 \, \text{cm} = 192 \, \text{cm}^2.
\]
2. Calculate the area of one square:
\[
\text{Area of one square} = \text{side} \times \text{side} = 2 \, \text{cm} \times 2 \, \text{cm} = 4 \, \text{cm}^2.
\]
3. Determine how many squares can fit into the rectangle by dividing the area of the rectangle by the area of one square:
\[
\text{Number of squares} = \frac{\text{Area of the rectangle}}{\text{Area of one square}} = \frac{192 \, \text{cm}^2}{4 \, \text{cm}^2} = 48.
\]
Thus, the number of squares with a side length of 2 cm that can cover the surface of the rectangle is \( \boxed{48} \).
1. Calculate the area of the rectangle:
\[
\text{Area of the rectangle} = \text{length} \times \text{width} = 24 \, \text{cm} \times 8 \, \text{cm} = 192 \, \text{cm}^2.
\]
2. Calculate the area of one square:
\[
\text{Area of one square} = \text{side} \times \text{side} = 2 \, \text{cm} \times 2 \, \text{cm} = 4 \, \text{cm}^2.
\]
3. Determine how many squares can fit into the rectangle by dividing the area of the rectangle by the area of one square:
\[
\text{Number of squares} = \frac{\text{Area of the rectangle}}{\text{Area of one square}} = \frac{192 \, \text{cm}^2}{4 \, \text{cm}^2} = 48.
\]
Thus, the number of squares with a side length of 2 cm that can cover the surface of the rectangle is \( \boxed{48} \).