The number of bugs doubles every 4 days. If the bug population starts with 6 bugs, then the equation A(t)=6(2)^0.25t can represent the number of bugs. Find the value for A(8)

the number of bugs after 8 days is...

1 answer

To calculate the number of bugs after 8 days using the given equation \( A(t) = 6(2)^{0.25t} \), we will substitute \( t = 8 \) into the equation.

\[ A(8) = 6(2)^{0.25 \times 8} \]

First, calculate \( 0.25 \times 8 \):

\[ 0.25 \times 8 = 2 \]

Now substitute this back into the equation:

\[ A(8) = 6(2)^{2} \]

Next, calculate \( (2)^{2} \):

\[ (2)^{2} = 4 \]

Now substitute this value back into the expression for \( A(8) \):

\[ A(8) = 6 \times 4 \]

Now complete the multiplication:

\[ A(8) = 24 \]

Therefore, the number of bugs after 8 days is \( \boxed{24} \).