How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.

1 answer

To find the amount of chocolate in a spherical chocolate truffle, we need to calculate the volume of the sphere using the formula:

\[ V = \frac{4}{3} \pi r^3 \]

where \( V \) is the volume and \( r \) is the radius of the sphere.

Given that the radius \( r \) of the truffle is 12 mm and using \( \pi \approx 3.14 \), we can substitute the values into the formula:

\[ V = \frac{4}{3} \times 3.14 \times (12)^3 \]

First, calculate \( 12^3 \):

\[ 12^3 = 12 \times 12 \times 12 = 144 \times 12 = 1728 \]

Now substituting this back into our volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 1728 \]

Calculate \( \frac{4}{3} \times 3.14 \):

\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]

Now multiply this by 1728:

\[ V \approx 4.1867 \times 1728 \approx 7224.3836 \]

Rounding to the nearest hundredth:

\[ V \approx 7224.38 \text{ mm}^3 \]

Thus, the volume of the spherical chocolate truffle is approximately 7224.38 mm³.