Question

Solve for y:
minus, 14, y, equals, 42−14y=42

Answer 1

Plug in y, equals, minus, 3y=−3 into either equation and solve for xx
5, x, plus, 8, y, equals, minus, 14, or, minus, 3, x, minus, 2, y, equals, 05x+8y=−14or−3x−2y=0

Answer 2

Solve for y:
minus, 17, y, equals, 68−17y=68

Answer 3

Plug in y, equals, minus, 4y=−4 into either equation and solve for xx
minus, x, minus, 2, y, equals, 13, or, 6, x, minus, 5, y, equals, minus, 10−x−2y=13or6x−5y=−10

Answer 4

To solve the equation \(-14y = 42\), you can follow these steps:

1. Divide both sides of the equation by \(-14\):

\[
y = \frac{42}{-14}
\]

2. Simplify the right side:

\[
y = -3
\]

So, the solution is:

\[
y = -3
\]

Answer 5

Let's solve for \( x \) by substituting \( y = -3 \) into both equations.

1. **First Equation:**
\[
5x + 8y = -14
\]
Substitute \( y = -3 \):
\[
5x + 8(-3) = -14
\]
This simplifies to:
\[
5x - 24 = -14
\]
Now, add 24 to both sides:
\[
5x = -14 + 24
\]
\[
5x = 10
\]
Finally, divide both sides by 5:
\[
x = 2
\]

2. **Second Equation:**
\[
-3x - 2y = 0
\]
Substitute \( y = -3 \):
\[
-3x - 2(-3) = 0
\]
This simplifies to:
\[
-3x + 6 = 0
\]
Now, subtract 6 from both sides:
\[
-3x = -6
\]
Finally, divide both sides by -3:
\[
x = 2
\]

In both equations, we find that \( x = 2 \).

So the solutions are:
\[
x = 2 \quad \text{and} \quad y = -3
\]

Answer 6

To solve the equation \(-17y = 68\), follow these steps:

1. Divide both sides of the equation by \(-17\):

\[
y = \frac{68}{-17}
\]

2. Simplify the right side:

\[
y = -4
\]

So the solution is:

\[
y = -4
\]

Answer 7

Let's solve for \( x \) by substituting \( y = -4 \) into both equations.

1. **First Equation:**
\[
-x - 2y = 13
\]
Substitute \( y = -4 \):
\[
-x - 2(-4) = 13
\]
This simplifies to:
\[
-x + 8 = 13
\]
Now, subtract 8 from both sides:
\[
-x = 13 - 8
\]
\[
-x = 5
\]
Now, multiply by -1:
\[
x = -5
\]

2. **Second Equation:**
\[
6x - 5y = -10
\]
Substitute \( y = -4 \):
\[
6x - 5(-4) = -10
\]
This simplifies to:
\[
6x + 20 = -10
\]
Now, subtract 20 from both sides:
\[
6x = -10 - 20
\]
\[
6x = -30
\]
Now, divide by 6:
\[
x = -5
\]

In both equations, we find that \( x = -5 \).

So the solutions are:
\[
x = -5 \quad \text{and} \quad y = -4
\]