To find the zeros of the polynomial \( g(x) = (x - 7)(3x - 5) \) using the Factor Theorem, we need to set \( g(x) = 0 \) and solve for \( x \).
- Set each factor equal to zero:
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For the first factor: \( x - 7 = 0 \) \[ x = 7 \]
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For the second factor: \( 3x - 5 = 0 \) \[ 3x = 5 \implies x = \frac{5}{3} \]
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So, the zeros of \( g(x) \) are \( x = 7 \) and \( x = \frac{5}{3} \).
Among the options provided:
- \( x = -5 \) (not a zero)
- \( x = -\frac{5}{3} \) (not a zero)
- \( x = -7 \) (not a zero)
- \( x = 7 \) (this is a zero)
The correct response is \( x = 7 \).