Given f(x)=4x2−10x−3 , according to the Remainder Theorem, f(2) can be found by finding the remainder of which of the following division quotients?(1 point) Responses (4x2−10x−3)÷2 left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by 2 (4x2−10x−3)÷x left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by x (4x2−10x−3)÷(x+2) left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x plus 2 right parenthesis (4x2−10x−3)÷(x−2) left parenthesis 4 x squared minus 10 x minus 3 right parenthesis divided by left parenthesis x minus 2 right parenthesis
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According to the Remainder Theorem, to find \( f(a) \) for a polynomial \( f(x) \), you can divide \( f(x) \) by \( (x - a) \) and the remainder of this division will be equal to \( f(a) \).
In this case, you want to find \( f(2) \). Therefore, you need to divide \( f(x) = 4x^2 - 10x - 3 \) by \( (x - 2) \).
Thus, the correct response is:
\((4x^2 - 10x - 3) \div (x - 2)\)
This division will give you the remainder, which is equal to \( f(2) \).
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