Question

Question
Place the numbers in descending order.

2.3 × 10^−10
; 3.2 × 10^−10
; 2.3 × 10^−12
; 2.3 × 10^−8

Answer 1

To place the numbers in descending order, it helps to first express each number in standard decimal notation:

1. \(2.3 \times 10^{-10} = 0.00000000023\)
2. \(3.2 \times 10^{-10} = 0.00000000032\)
3. \(2.3 \times 10^{-12} = 0.0000000000023\)
4. \(2.3 \times 10^{-8} = 0.000000023\)

Now we can compare the numbers:

- \(2.3 \times 10^{-8} = 0.000000023\)
- \(2.3 \times 10^{-10} = 0.00000000023\)
- \(3.2 \times 10^{-10} = 0.00000000032\)
- \(2.3 \times 10^{-12} = 0.0000000000023\)

Arranging them in descending order gives:

1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)

So the final order is:

**2.3 × 10^−8 ; 3.2 × 10^−10 ; 2.3 × 10^−10 ; 2.3 × 10^−12**