To determine the opportunity cost of each car on the production possibilities frontier (PPF) for sofas and cars, we first need to calculate the slope of the PPF.
From the given points on the PPF where:
- Point A: (0, 900) - maximum sofas
- Point B: (200, 600)
- Point C: (400, 300)
- Point D: (600, 0) - maximum cars
We can calculate the slope of the PPF section from Point B to Point C. The change in the number of cars (y-axis) is from 600 to 300, which is a decrease of 300 cars. The change in the number of sofas (x-axis) is from 200 to 400, which is an increase of 200 sofas.
The formula for slope (m) between two points (x1, y1) and (x2, y2) is:
\[ m = \frac{y2 - y1}{x2 - x1} \]
Using the points B (200, 600) and C (400, 300):
\[ m = \frac{300 - 600}{400 - 200} = \frac{-300}{200} = -\frac{3}{2} \]
The negative sign indicates a trade-off; as you produce more cars, you have to give up sofas. The absolute value of the slope, \( \frac{3}{2} \), represents the opportunity cost of producing one car.
Since here we need to calculate the opportunity cost of each car:
- The slope of the PPF from Point B to Point C indicates that for every car produced, you give up \( \frac{3}{2} \) sofas.
- Therefore, the opportunity cost of one car is \( \frac{3}{2} \) sofas.
This means that the correct answer is:
d. the slope of the production possibilities frontier, or 3/2 sofas.