Question

Find the volume of a ping pong ball with a radius of 1 inch

Answer 1

The volume \( V \) of a sphere can be calculated using the formula:

\[
V = \frac{4}{3} \pi r^3
\]

where \( r \) is the radius of the sphere. Given that the radius of the ping pong ball is 1 inch, we can substitute \( r = 1 \) inch into the formula:

\[
V = \frac{4}{3} \pi (1)^3
\]

Calculating this, we get:

\[
V = \frac{4}{3} \pi \cdot 1 = \frac{4}{3} \pi
\]

To find a numerical approximation, we can use \( \pi \approx 3.14159 \):

\[
V \approx \frac{4}{3} \cdot 3.14159 \approx 4.18879
\]

Therefore, the volume of the ping pong ball is approximately

\[
V \approx 4.19 \text{ cubic inches}
\]

So, the exact volume is

\[
\frac{4}{3} \pi \text{ cubic inches,}
\]

or approximately \( 4.19 \) cubic inches.