Question

y=2x2+7x List smaller solution first.

Answer 1

To find the solutions to the equation \( y = 2x^2 + 7x \), we first need to set it equal to zero:

\[
2x^2 + 7x = 0
\]

Now, we can factor the equation:

\[
x(2x + 7) = 0
\]

This gives us two solutions:

1. \( x = 0 \)
2. \( 2x + 7 = 0 \)

For the second solution, we can solve for \( x \):

\[
2x = -7 \quad \Rightarrow \quad x = -\frac{7}{2}
\]

So the solutions to the equation are:

1. \( x = -\frac{7}{2} \)
2. \( x = 0 \)

Listing the smaller solution first:

\[
x = -\frac{7}{2}, \quad x = 0
\]