Annette’s soccer team will play 15 games this season. That is 7 games fewer than 2 times the number of games they played last season. How many games did they play last season? Represent this problem with an equation in the form px+q=r

Question

.(1 point)
Responses

15−7=2x
15 minus 7 equals 2 x

2x+7=15
2 x plus 7 equals 15

7−2x=15
7 minus 2 x equals 15

2x−7=15

Answer 1

To represent the problem with an equation, we start with the information given:

1. Let \( x \) be the number of games played last season.
2. The team will play 15 games this season.
3. The number of games played this season (15 games) is 7 games fewer than 2 times the number of games played last season.

We can express this relationship as:

\[ 15 = 2x - 7 \]

Now let's rearrange the equation to match the form \( px + q = r \):

Adding 7 to both sides gives:

\[ 15 + 7 = 2x \]

This simplifies to:

\[ 22 = 2x \]

Now, to write it in the standard form \( px + q = r \):

Rearranging gives:

\[ 2x - 22 = 0 \]

Since the choices you provided do not exactly match that form, let's compare them:

1. \( 15 - 7 = 2x \) simplifies to \( 8 = 2x \) (Not exactly the issue).
2. \( 2x + 7 = 15 \) simplifies, leads to \( 2x = 8 \)(which is closer).
3. \( 7 - 2x = 15 \) leads to a negative equation which is transformed incorrectly.
4. \( 2x - 7 = 15 \) leads to \( 2x - 22 = 0\), which is the rearrangement of our original.

Out of the options, the correct choice is:

2x + 7 = 15 (this leads to solving x accurately).

So the answer is:

2x + 7 = 15 (2 x plus 7 equals 15).