Transform the linear equation 4x − 8y = 24 to slope-intercept form.

1 answer

To transform the linear equation \( 4x - 8y = 24 \) into slope-intercept form (\(y = mx + b\)), we need to solve for \(y\).

Starting with the original equation:

\[ 4x - 8y = 24 \]

  1. Subtract \(4x\) from both sides:

\[ -8y = -4x + 24 \]

  1. Divide every term by \(-8\) to solve for \(y\):

\[ y = \frac{-4x}{-8} + \frac{24}{-8} \]

  1. Simplify the fractions:

\[ y = \frac{1}{2}x - 3 \]

Now we have the equation in slope-intercept form:

\[ y = \frac{1}{2}x - 3 \]

Here, the slope \(m\) is \(\frac{1}{2}\) and the y-intercept \(b\) is \(-3\).