ntify the slope and the y-intercept of the equation 4x − 3y = 12. (1 point)

The slope is 4, and the y-intercept is (0, 12).
The slope is − , and the y-intercept is . 4
3 (0, 4)
The slope is , and the y-intercept is . 4
3 (0, 4)
The slope is , and the y-intercept is . 4
3 (0, − 4)

1 answer

To identify the slope and the y-intercept of the equation \(4x - 3y = 12\), we can rewrite the equation in slope-intercept form, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Starting with the given equation:

\[ 4x - 3y = 12 \]

We can isolate \(y\):

  1. Subtract \(4x\) from both sides:

    \[-3y = -4x + 12\]

  2. Divide by \(-3\):

    \[y = \frac{4}{3}x - 4\]

From this, we can see that the slope \(m\) is \(\frac{4}{3}\), and the y-intercept \(b\) is \(-4\).

Thus, the slope is \(\frac{4}{3}\) and the y-intercept is \((0, -4)\).

So, the correct identification is:

The slope is \(\frac{4}{3}\), and the y-intercept is \((0, -4)\).

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