Question

Identify the slope and the -
intercept of the equation
. (1 point)
y
4x − 3y = 12
The slope is 4, and the
y-intercept is (0, 12).
The slope is , and
the y-intercept is
.
4
3
(0, 4)
The slope is , and
the y-intercept is
.
−
4
3
(0, 4)
The slope is , and
the y-intercept is
.
4
3
(0, − 4

Answer 1

To find the slope and y-intercept of the equation \(4x - 3y = 12\), we can start by rewriting it in slope-intercept form, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

1. Start with the original equation:
\[
4x - 3y = 12
\]

2. Solve for \(y\):
\[
-3y = -4x + 12
\]

3. Divide everything by \(-3\):
\[
y = \frac{4}{3}x - 4
\]

Now, the equation is in the slope-intercept form \(y = mx + b\).

From this equation, we can identify:
- The slope \(m = \frac{4}{3}\)
- The y-intercept \(b = -4\) (which corresponds to the point \((0, -4)\))

Thus, the slope is \(\frac{4}{3}\), and the y-intercept is \((0, -4)\).