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Graph the equation

using slopeintercept form. (1 point)
9 − x = y
3
2
tell me the two points

3 answers

To rewrite the equation \( 9 - x = y \) in slope-intercept form (\( y = mx + b \)), we can manipulate the equation as follows:

\[ y = -x + 9 \]

From this equation, we can identify the slope (\( m \)) and the y-intercept (\( b \)):

  • The slope \( m = -1 \)
  • The y-intercept \( b = 9 \) (which means the line crosses the y-axis at the point (0, 9)).

To find two points on the line, we can choose a couple of values for \( x \) and calculate the corresponding \( y \) values.

  1. Let’s choose \( x = 0 \): \[ y = -0 + 9 = 9 \quad \Rightarrow \quad (0, 9) \]

  2. Let’s choose \( x = 3 \): \[ y = -3 + 9 = 6 \quad \Rightarrow \quad (3, 6) \]

The two points we found are:

  1. \( (0, 9) \)
  2. \( (3, 6) \)

You can graph these points and draw a line through them to represent the equation \( y = -x + 9 \).

wrong

I apologize for any confusion. Let's go through the steps again.

We start with the equation you've provided:

\[ 9 - x = y \]

First, we rearrange it into slope-intercept form \((y = mx + b)\):

\[ y = -x + 9 \]

This is already in slope-intercept form, where:

  • The slope \(m = -1\)
  • The y-intercept \(b = 9\) (which means it crosses the y-axis at (0, 9)).

To find two points, we can substitute different values for \(x\):

  1. When \(x = 0\): \[ y = -0 + 9 = 9 \] So the point is \((0, 9)\).

  2. When \(x = 3\): \[ y = -3 + 9 = 6 \] So the point is \((3, 6)\).

  3. When \(x = 9\): \[ y = -9 + 9 = 0 \] So the point is \((9, 0)\).

Thus, two points on the graph of the equation \(y = -x + 9\) are:

  1. \( (0, 9) \)
  2. \( (3, 6) \)

And if you need any additional points, you can choose values for \(x\) accordingly. I hope this clarifies the points derived from the equation! If there was another aspect you meant when you said "wrong," please let me know so I can assist you better.