Asked by Jean-Luc
Graph the equation
using slopeintercept form. (1 point)
9 − x = y
3
2
tell me the two points
using slopeintercept form. (1 point)
9 − x = y
3
2
tell me the two points
Answers
Answered by
Jean-Luc
wrong
Answered by
GPT-4o mini
To rewrite the equation \( 9 - x = y \) in slope-intercept form (\( y = mx + b \)), we can manipulate the equation as follows:
\[
y = -x + 9
\]
From this equation, we can identify the slope (\( m \)) and the y-intercept (\( b \)):
- The slope \( m = -1 \)
- The y-intercept \( b = 9 \) (which means the line crosses the y-axis at the point (0, 9)).
To find two points on the line, we can choose a couple of values for \( x \) and calculate the corresponding \( y \) values.
1. Let’s choose \( x = 0 \):
\[
y = -0 + 9 = 9 \quad \Rightarrow \quad (0, 9)
\]
2. Let’s choose \( x = 3 \):
\[
y = -3 + 9 = 6 \quad \Rightarrow \quad (3, 6)
\]
The two points we found are:
1. \( (0, 9) \)
2. \( (3, 6) \)
You can graph these points and draw a line through them to represent the equation \( y = -x + 9 \).
\[
y = -x + 9
\]
From this equation, we can identify the slope (\( m \)) and the y-intercept (\( b \)):
- The slope \( m = -1 \)
- The y-intercept \( b = 9 \) (which means the line crosses the y-axis at the point (0, 9)).
To find two points on the line, we can choose a couple of values for \( x \) and calculate the corresponding \( y \) values.
1. Let’s choose \( x = 0 \):
\[
y = -0 + 9 = 9 \quad \Rightarrow \quad (0, 9)
\]
2. Let’s choose \( x = 3 \):
\[
y = -3 + 9 = 6 \quad \Rightarrow \quad (3, 6)
\]
The two points we found are:
1. \( (0, 9) \)
2. \( (3, 6) \)
You can graph these points and draw a line through them to represent the equation \( y = -x + 9 \).
Answered by
GPT-4o mini
I apologize for any confusion. Let's go through the steps again.
We start with the equation you've provided:
\[
9 - x = y
\]
First, we rearrange it into slope-intercept form \((y = mx + b)\):
\[
y = -x + 9
\]
This is already in slope-intercept form, where:
- The slope \(m = -1\)
- The y-intercept \(b = 9\) (which means it crosses the y-axis at (0, 9)).
To find two points, we can substitute different values for \(x\):
1. **When \(x = 0\)**:
\[
y = -0 + 9 = 9
\]
So the point is \((0, 9)\).
2. **When \(x = 3\)**:
\[
y = -3 + 9 = 6
\]
So the point is \((3, 6)\).
3. **When \(x = 9\)**:
\[
y = -9 + 9 = 0
\]
So the point is \((9, 0)\).
Thus, two points on the graph of the equation \(y = -x + 9\) are:
1. \( (0, 9) \)
2. \( (3, 6) \)
And if you need any additional points, you can choose values for \(x\) accordingly. I hope this clarifies the points derived from the equation! If there was another aspect you meant when you said "wrong," please let me know so I can assist you better.
We start with the equation you've provided:
\[
9 - x = y
\]
First, we rearrange it into slope-intercept form \((y = mx + b)\):
\[
y = -x + 9
\]
This is already in slope-intercept form, where:
- The slope \(m = -1\)
- The y-intercept \(b = 9\) (which means it crosses the y-axis at (0, 9)).
To find two points, we can substitute different values for \(x\):
1. **When \(x = 0\)**:
\[
y = -0 + 9 = 9
\]
So the point is \((0, 9)\).
2. **When \(x = 3\)**:
\[
y = -3 + 9 = 6
\]
So the point is \((3, 6)\).
3. **When \(x = 9\)**:
\[
y = -9 + 9 = 0
\]
So the point is \((9, 0)\).
Thus, two points on the graph of the equation \(y = -x + 9\) are:
1. \( (0, 9) \)
2. \( (3, 6) \)
And if you need any additional points, you can choose values for \(x\) accordingly. I hope this clarifies the points derived from the equation! If there was another aspect you meant when you said "wrong," please let me know so I can assist you better.