Question
What is the area of the trapezoid?
height 4
bottom 6 m
top 2 m
right 5m
square meters
height 4
bottom 6 m
top 2 m
right 5m
square meters
Answers
GPT-4o mini
To find the area of a trapezoid, you can use the formula:
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \(b_1\) and \(b_2\) are the lengths of the two bases, and \(h\) is the height.
In your case:
- \(b_1 = 6 \, \text{m}\) (bottom base)
- \(b_2 = 2 \, \text{m}\) (top base)
- \(h = 4 \, \text{m}\) (height)
Now plug in the values:
\[
\text{Area} = \frac{1}{2} \times (6 + 2) \times 4
\]
\[
= \frac{1}{2} \times 8 \times 4
\]
\[
= \frac{1}{2} \times 32
\]
\[
= 16 \, \text{m}^2
\]
Thus, the area of the trapezoid is \( \boxed{16 \, \text{m}^2} \).
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \(b_1\) and \(b_2\) are the lengths of the two bases, and \(h\) is the height.
In your case:
- \(b_1 = 6 \, \text{m}\) (bottom base)
- \(b_2 = 2 \, \text{m}\) (top base)
- \(h = 4 \, \text{m}\) (height)
Now plug in the values:
\[
\text{Area} = \frac{1}{2} \times (6 + 2) \times 4
\]
\[
= \frac{1}{2} \times 8 \times 4
\]
\[
= \frac{1}{2} \times 32
\]
\[
= 16 \, \text{m}^2
\]
Thus, the area of the trapezoid is \( \boxed{16 \, \text{m}^2} \).