It seems like there's a misunderstanding in the phrasing of your question. A right triangle's sides should be lengths (in meters) rather than squared (in square meters).
Let's assume you meant that the lengths of the legs of the right triangle are 9 meters and 16 meters.
Step 1: Find the area of the triangle.
The area \( A \) of a right triangle can be calculated using the formula:
\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]
Here, we can take the two legs of the triangle as the base and height:
\[ A = \frac{1}{2} \times 9 , \text{m} \times 16 , \text{m} \] \[ A = \frac{1}{2} \times 144 , \text{m}^2 \] \[ A = 72 , \text{m}^2 \]
So, the area of the triangle is \( 72 , \text{m}^2 \).
Step 2: Find the length of the hypotenuse \( c \).
To find the length of the hypotenuse \( c \), we can use the Pythagorean Theorem:
\[ c^2 = a^2 + b^2 \]
Let \( a = 9 , \text{m} \) and \( b = 16 , \text{m} \):
\[ c^2 = 9^2 + 16^2 \] \[ c^2 = 81 + 256 \] \[ c^2 = 337 \] \[ c = \sqrt{337} \approx 18.36 , \text{m} \]
Summary:
- The area of the triangle is \( 72 , \text{m}^2 \).
- The length of the hypotenuse \( c \) is approximately \( 18.36 , \text{m} \).
If you meant something different, please clarify!