a. To prove that the 8-ball at point I is equidistant from the hole at point F and the hole at point C, we can use the properties of a perpendicular bisector. First, since line segment overline GH is the perpendicular bisector of overline FC, it means that it intersects overline FC at point J and that point J is the midpoint of overline FC. This tells us that any point on overline GH, including point I, is the same distance from point F and point C. Therefore, the 8-ball at point I is equidistant from both holes!
b. Another point that would also be equidistant from points F and C is point J, where the perpendicular bisector overline GH intersects overline FC. We know this because point J is the midpoint of overline FC, making it the same distance to both point F and point C. Just like point I, point J is also on the perpendicular bisector, which means it's equidistant from the two holes.