To find the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height of the cone.
From your question, it seems that the cone has:
- Height \( h = 6 \) inches
- Diameter \( d = 2 \) inches, which gives a radius \( r = \frac{d}{2} = \frac{2}{2} = 1 \) inch.
Now, plug the values into the volume formula.
\[ V = \frac{1}{3} \cdot 3.14 \cdot (1)^2 \cdot 6 \]
Calculating that:
\[ V = \frac{1}{3} \cdot 3.14 \cdot 1 \cdot 6 \]
\[ V = \frac{1}{3} \cdot 18.84 \]
\[ V = 6.28 \]
Rounding to the nearest cubic inch gives us: \[ V \approx 6 \text{ cubic inches} \]
However, none of the provided options match this result. re-check the provided values or question context to ensure accuracy. Given the provided options:
- 25 cubic inches
- 24 cubic inches
- 75 cubic inches
- 13 cubic inches
It seems there may have been a mistake in interpreting the values, as the calculated volume does not match any of them. Adjust the values if necessary or provide more accurate dimensions. If the height of the cone is incorrect, try recalculating by confirming all dimensions.
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