To find the value of \(\sqrt{b} + 12\) when \(b = 24\), we first calculate \(\sqrt{24}\).
\[ \sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2\sqrt{6} \]
Now, we add 12 to this result:
\[ \sqrt{b} + 12 = 2\sqrt{6} + 12 \]
Thus, the final expression is:
\[ 2\sqrt{6} + 12 \]
If you need a decimal approximation for better understanding, consider \(\sqrt{6} \approx 2.45\):
\[ 2\sqrt{6} \approx 2 \times 2.45 = 4.9 \]
So:
\[ 2\sqrt{6} + 12 \approx 4.9 + 12 \approx 16.9 \]
In summary, the expression evaluates to \(2\sqrt{6} + 12\) or approximately \(16.9\).