To find the value of \( \sqrt{12} + x \) when \( x = 4 \), we first need to calculate \( \sqrt{12} \).
We can simplify \( \sqrt{12} \): \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \]
Now, substituting \( x = 4 \): \[ \sqrt{12} + x = 2\sqrt{3} + 4 \]
Thus, the final result is: \[ 2\sqrt{3} + 4 \]