To analyze the quadratic function \( y = x^2 - 8x \), we can determine the key points such as the vertex, x-intercepts, and y-intercept.
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Vertex: The vertex of a quadratic function in standard form \( y = ax^2 + bx + c \) can be found using the formula for the x-coordinate of the vertex, \( x = -\frac{b}{2a} \). Here, \( a = 1 \) and \( b = -8 \).
\[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
To find the y-coordinate of the vertex, substitute \( x = 4 \) back into the equation:
\[ y = (4)^2 - 8(4) = 16 - 32 = -16 \]
Therefore, the vertex is \( (4, -16) \).
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X-Intercepts: The x-intercepts occur when \( y = 0 \):
\[ 0 = x^2 - 8x \]
Factoring gives:
\[ 0 = x(x - 8) \]
Setting each factor to zero gives \( x = 0 \) and \( x = 8 \). Thus, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
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Y-Intercept: The y-intercept occurs when \( x = 0 \):
\[ y = 0^2 - 8(0) = 0 \]
Therefore, the y-intercept is \( (0, 0) \).
Summary of Key Points:
- Vertex: \( (4, -16) \)
- X-Intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-Intercept: \( (0, 0) \)
Correct Response:
Based on the analysis, the correct response regarding the key points on the graph would likely be:
- x-intercepts: \( (0, 0) \) and \( (8, 0) \)
- y-intercept: \( (0, 0) \)
- vertex: \( (4, -16) \)