Question

Assume 2.5 grams of benzion and 12.0 mL of 15.8 M nitric acid (density = 1.51 g/mL) was used in the experiment . What is the mole to mole ratio of benzion and nitrate ion.

Answer 1

moles benzoin = grams/molar mass
moles HNO3 = (1.51 g/mL x 12.0 mL)/molar mass,
You can do the ratio.

Answer 2

.0118 moles benzoin
.288 moles HNO3
How do I do the ratio?

Answer 3

If it's the ratio of the moles you have to start with it is just 0.0118/0.288 = ??

It's another ball game if you want the ratio of the REACTING materials.