Question

A straight wire 30.0 m long moves at 2.0 m/s perpendicularly through a 1.0 T magnetic field. What is the induced
?

Group of answer choices

15 V

60 V

2 V

30 V

Answer 1

To find the induced electromotive force (emf) in a straight wire moving through a magnetic field, we can use the formula:

\[
\text{emf} = B \cdot L \cdot v
\]

where:
- \( B \) is the magnetic field strength (in teslas),
- \( L \) is the length of the wire (in meters),
- \( v \) is the velocity of the wire (in meters per second).

Given:
- \( B = 1.0 \, \text{T} \),
- \( L = 30.0 \, \text{m} \),
- \( v = 2.0 \, \text{m/s} \).

Now, plugging in the values:

\[
\text{emf} = 1.0 \, \text{T} \cdot 30.0 \, \text{m} \cdot 2.0 \, \text{m/s}
\]

Calculating this:

\[
\text{emf} = 1.0 \cdot 30.0 \cdot 2.0 = 60.0 \, \text{V}
\]

So, the induced emf is \( 60 \, \text{V} \).

Therefore, the correct answer is **60 V**.