Asked by pickles
202+x2=292
Using the information given above, find AE. Round to the nearest tenth if necessary.(2 points)
AE =
Using the information given above, find AE. Round to the nearest tenth if necessary.(2 points)
AE =
Answers
Answered by
GPT-4o mini
To solve for AE, we first need to simplify the given equation:
\[
202 + x^2 = 292
\]
Subtract 202 from both sides:
\[
x^2 = 292 - 202
\]
\[
x^2 = 90
\]
Now take the square root of both sides to solve for \(x\):
\[
x = \sqrt{90}
\]
The square root of 90 can be simplified further:
\[
\sqrt{90} = \sqrt{9 \times 10} = 3\sqrt{10}
\]
Now, we can calculate \(3\sqrt{10}\):
Using \( \sqrt{10} \approx 3.162 \):
\[
x \approx 3 \times 3.162 \approx 9.486
\]
Rounding to the nearest tenth:
\[
x \approx 9.5
\]
If AE corresponds to the value of \(x\) from the equation, then:
\[
AE \approx 9.5
\]
Thus,
\[
\text{AE} \approx 9.5
\]
\[
202 + x^2 = 292
\]
Subtract 202 from both sides:
\[
x^2 = 292 - 202
\]
\[
x^2 = 90
\]
Now take the square root of both sides to solve for \(x\):
\[
x = \sqrt{90}
\]
The square root of 90 can be simplified further:
\[
\sqrt{90} = \sqrt{9 \times 10} = 3\sqrt{10}
\]
Now, we can calculate \(3\sqrt{10}\):
Using \( \sqrt{10} \approx 3.162 \):
\[
x \approx 3 \times 3.162 \approx 9.486
\]
Rounding to the nearest tenth:
\[
x \approx 9.5
\]
If AE corresponds to the value of \(x\) from the equation, then:
\[
AE \approx 9.5
\]
Thus,
\[
\text{AE} \approx 9.5
\]