Question

Find the midpoint of segment AB where A (-3,2) and B (3,-2).

Answer 1

To find the midpoint of segment AB, we use the midpoint formula:

\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

where \( (x_1, y_1) \) are the coordinates of point A and \( (x_2, y_2) \) are the coordinates of point B.

Given:
- A (-3, 2) → \( x_1 = -3 \), \( y_1 = 2 \)
- B (3, -2) → \( x_2 = 3 \), \( y_2 = -2 \)

Now, we can substitute these values into the midpoint formula:

\[
\text{Midpoint} = \left( \frac{-3 + 3}{2}, \frac{2 + (-2)}{2} \right)
\]

Calculating the x-coordinate:

\[
\frac{-3 + 3}{2} = \frac{0}{2} = 0
\]

Calculating the y-coordinate:

\[
\frac{2 - 2}{2} = \frac{0}{2} = 0
\]

Thus, the midpoint of segment AB is:

\[
\text{Midpoint} = (0, 0)
\]