Asked by Anonymous
A .055 gram sample of aluminum hydroxide is reacted with .200M hydrochloric acid. How many mL of the acid are needed to neutralize the aluminum hydroxide?
Answers
Answered by
DrBob222
1. Write and balance the equation.
2. Convert 0.055 g Al(OH)3 to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Al to moles HCl.
4. Molarity = moles HCl/L of HCl.
You know moles HCl and Molarity; calculate L of HCl.
2. Convert 0.055 g Al(OH)3 to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Al to moles HCl.
4. Molarity = moles HCl/L of HCl.
You know moles HCl and Molarity; calculate L of HCl.
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