Question

How much charge flows from a 3 V battery when it is connected to a 9.00 microfarad capacitor?

Group of answer choices

1.35x10-5 C

3.75x10-5 C

1.5 C

2.7x10-5 C

Answer 1

To calculate the charge (\(Q\)) that flows from a battery to a capacitor, you can use the formula:

\[
Q = C \times V
\]

where:
- \(Q\) is the charge in coulombs (C),
- \(C\) is the capacitance in farads (F),
- \(V\) is the voltage in volts (V).

Given:
- \(C = 9.00 \, \mu\text{F} = 9.00 \times 10^{-6} \, \text{F}\)
- \(V = 3 \, \text{V}\)

Now, substitute the values into the formula:

\[
Q = (9.00 \times 10^{-6} \, \text{F})(3 \, \text{V}) = 27.0 \times 10^{-6} \, \text{C} = 2.7 \times 10^{-5} \, \text{C}
\]

Therefore, the amount of charge that flows from the 3 V battery when connected to a 9.00 microfarad capacitor is

\[
\text{2.7} \times 10^{-5} \, \text{C}
\]

So the correct answer is:

**2.7x10-5 C**