To solve the system of equations
- \( 5x + 8y = -14 \)
- \( -3x - 2y = 0 \)
we will use the method of elimination (combining the equations). To make the calculations easier, we will first express one equation in a form that allows us to eliminate one variable.
Step 1: Rearranging the second equation to express \(y\):
From the second equation, we can express \(y\) in terms of \(x\):
\[ -3x - 2y = 0 \implies 2y = -3x \implies y = -\frac{3}{2}x \]
Step 2: Substitute \(y\) into the first equation:
Now that we have \(y\) in terms of \(x\), we can substitute it into the first equation:
\[ 5x + 8\left(-\frac{3}{2}x\right) = -14 \]
Step 3: Simplifying the equation:
\[ 5x - 12x = -14 \] \[ -7x = -14 \]
Step 4: Solve for \(x\):
\[ x = \frac{-14}{-7} = 2 \]
Step 5: Substitute \(x\) back to find \(y\):
Now substitute \(x = 2\) back into the equation for \(y\):
\[ y = -\frac{3}{2}(2) = -3 \]
Final Solution:
The solutions to the system of equations are:
\[ x = 2, \quad y = -3 \]
Thus, the ordered pair that solves the system is \((2, -3)\).