Question
Question
Determine if the given equation if BALANCED or UNBALANCED. (5 points)(5 points)
BALANCED UNBALANCED
N
2
+
H
2
→
2
N
H
3
2
C
2
H
6
+
7
O
2
→
4
C
O
2
+
6
H
2
O
4
Z
n
S
+
6
O
2
→
4
Z
n
O
+
4
S
O
2
2
F
e
2
O
3
+
3
C
→
F
e
+
3
C
O
2
C
3
H
8
+
5
O
2
→
3
C
O
2
+
4
H
2
O
Determine if the given equation if BALANCED or UNBALANCED. (5 points)(5 points)
BALANCED UNBALANCED
N
2
+
H
2
→
2
N
H
3
2
C
2
H
6
+
7
O
2
→
4
C
O
2
+
6
H
2
O
4
Z
n
S
+
6
O
2
→
4
Z
n
O
+
4
S
O
2
2
F
e
2
O
3
+
3
C
→
F
e
+
3
C
O
2
C
3
H
8
+
5
O
2
→
3
C
O
2
+
4
H
2
O
Answers
GPT-4o mini
To determine if the given chemical equations are balanced or unbalanced, we need to count the number of atoms for each element on both sides of the equations.
### 1. \( N_2 + H_2 → 2NH_3 \)
- Left side:
- N: 2
- H: 2
- Right side:
- N: 2 (from \(2NH_3\))
- H: 6 (from \(2NH_3\))
**Total:**
- N: 2, H: 2 (Left) vs N: 2, H: 6 (Right)
**Conclusion:** UNBALANCED
### 2. \( 2C_2H_6 + 7O_2 → 4CO_2 + 6H_2O \)
- Left side:
- C: 4 (from \(2C_2H_6\))
- H: 12 (from \(2C_2H_6\))
- O: 14 (from \(7O_2\))
- Right side:
- C: 4 (from \(4CO_2\))
- H: 12 (from \(6H_2O\))
- O: 14 (from \(4CO_2\) and \(6H_2O\))
**Total:**
- C: 4, H: 12, O: 14 (Left) vs C: 4, H: 12, O: 14 (Right)
**Conclusion:** BALANCED
### 3. \( 4ZnS + 6O_2 → 4ZnO + 4SO_2 \)
- Left side:
- Zn: 4
- S: 4 (from \(4ZnS\))
- O: 12 (from \(6O_2\))
- Right side:
- Zn: 4 (from \(4ZnO\))
- S: 4 (from \(4SO_2\))
- O: 12 (from \(4ZnO\) and \(4SO_2\))
**Total:**
- Zn: 4, S: 4, O: 12 (Left) vs Zn: 4, S: 4, O: 12 (Right)
**Conclusion:** BALANCED
### 4. \( 2Fe_2O_3 + 3C → 4Fe + 3CO_2 \)
- Left side:
- Fe: 4 (from \(2Fe_2O_3\))
- O: 6 (from \(2Fe_2O_3\))
- C: 3
- Right side:
- Fe: 4 (from \(4Fe\))
- O: 6 (from \(3CO_2\))
- C: 3
**Total:**
- Fe: 4, O: 6, C: 3 (Left) vs Fe: 4, O: 6, C: 3 (Right)
**Conclusion:** BALANCED
### 5. \( C_3H_8 + 5O_2 → 3CO_2 + 4H_2O \)
- Left side:
- C: 3 (from \(C_3H_8\))
- H: 8 (from \(C_3H_8\))
- O: 10 (from \(5O_2\))
- Right side:
- C: 3 (from \(3CO_2\))
- H: 8 (from \(4H_2O\))
- O: 10 (from \(3CO_2\) and \(4H_2O\))
**Total:**
- C: 3, H: 8, O: 10 (Left) vs C: 3, H: 8, O: 10 (Right)
**Conclusion:** BALANCED
### Summary:
1. \( N_2 + H_2 → 2NH_3 \) : UNBALANCED
2. \( 2C_2H_6 + 7O_2 → 4CO_2 + 6H_2O \) : BALANCED
3. \( 4ZnS + 6O_2 → 4ZnO + 4SO_2 \) : BALANCED
4. \( 2Fe_2O_3 + 3C → 4Fe + 3CO_2 \) : BALANCED
5. \( C_3H_8 + 5O_2 → 3CO_2 + 4H_2O \) : BALANCED
### 1. \( N_2 + H_2 → 2NH_3 \)
- Left side:
- N: 2
- H: 2
- Right side:
- N: 2 (from \(2NH_3\))
- H: 6 (from \(2NH_3\))
**Total:**
- N: 2, H: 2 (Left) vs N: 2, H: 6 (Right)
**Conclusion:** UNBALANCED
### 2. \( 2C_2H_6 + 7O_2 → 4CO_2 + 6H_2O \)
- Left side:
- C: 4 (from \(2C_2H_6\))
- H: 12 (from \(2C_2H_6\))
- O: 14 (from \(7O_2\))
- Right side:
- C: 4 (from \(4CO_2\))
- H: 12 (from \(6H_2O\))
- O: 14 (from \(4CO_2\) and \(6H_2O\))
**Total:**
- C: 4, H: 12, O: 14 (Left) vs C: 4, H: 12, O: 14 (Right)
**Conclusion:** BALANCED
### 3. \( 4ZnS + 6O_2 → 4ZnO + 4SO_2 \)
- Left side:
- Zn: 4
- S: 4 (from \(4ZnS\))
- O: 12 (from \(6O_2\))
- Right side:
- Zn: 4 (from \(4ZnO\))
- S: 4 (from \(4SO_2\))
- O: 12 (from \(4ZnO\) and \(4SO_2\))
**Total:**
- Zn: 4, S: 4, O: 12 (Left) vs Zn: 4, S: 4, O: 12 (Right)
**Conclusion:** BALANCED
### 4. \( 2Fe_2O_3 + 3C → 4Fe + 3CO_2 \)
- Left side:
- Fe: 4 (from \(2Fe_2O_3\))
- O: 6 (from \(2Fe_2O_3\))
- C: 3
- Right side:
- Fe: 4 (from \(4Fe\))
- O: 6 (from \(3CO_2\))
- C: 3
**Total:**
- Fe: 4, O: 6, C: 3 (Left) vs Fe: 4, O: 6, C: 3 (Right)
**Conclusion:** BALANCED
### 5. \( C_3H_8 + 5O_2 → 3CO_2 + 4H_2O \)
- Left side:
- C: 3 (from \(C_3H_8\))
- H: 8 (from \(C_3H_8\))
- O: 10 (from \(5O_2\))
- Right side:
- C: 3 (from \(3CO_2\))
- H: 8 (from \(4H_2O\))
- O: 10 (from \(3CO_2\) and \(4H_2O\))
**Total:**
- C: 3, H: 8, O: 10 (Left) vs C: 3, H: 8, O: 10 (Right)
**Conclusion:** BALANCED
### Summary:
1. \( N_2 + H_2 → 2NH_3 \) : UNBALANCED
2. \( 2C_2H_6 + 7O_2 → 4CO_2 + 6H_2O \) : BALANCED
3. \( 4ZnS + 6O_2 → 4ZnO + 4SO_2 \) : BALANCED
4. \( 2Fe_2O_3 + 3C → 4Fe + 3CO_2 \) : BALANCED
5. \( C_3H_8 + 5O_2 → 3CO_2 + 4H_2O \) : BALANCED