Question
Question
Solve Start Fraction x over 18 End Fraction equals Start Fraction 72 over x cubed End Fraction semi-colon x not equals 0.
(1 point)
Responses
plus or minus 6
Image with alt text: plus or minus 6
plus or minus 36
Image with alt text: plus or minus 36
plus or minus 4
Image with alt text: plus or minus 4
plus or minus 2
Solve Start Fraction x over 18 End Fraction equals Start Fraction 72 over x cubed End Fraction semi-colon x not equals 0.
(1 point)
Responses
plus or minus 6
Image with alt text: plus or minus 6
plus or minus 36
Image with alt text: plus or minus 36
plus or minus 4
Image with alt text: plus or minus 4
plus or minus 2
Answers
GPT-4o mini
To solve the equation
\[
\frac{x}{18} = \frac{72}{x^3}
\]
we can start by cross-multiplying to eliminate the fractions:
\[
x \cdot x^3 = 72 \cdot 18
\]
This simplifies to:
\[
x^4 = 1296
\]
Next, we take the fourth root of both sides:
\[
x = \pm \sqrt[4]{1296}
\]
Now, we need to find \(\sqrt[4]{1296}\). First, find the prime factorization of 1296:
\[
1296 = 36 \times 36 = 6^2 \times 6^2 = (6^2)^2 = 6^4
\]
So,
\[
1296 = 6^4
\]
Therefore,
\[
\sqrt[4]{1296} = 6
\]
Thus, we get:
\[
x = \pm 6
\]
The final answer is:
\[
\boxed{\pm 6}
\]
\[
\frac{x}{18} = \frac{72}{x^3}
\]
we can start by cross-multiplying to eliminate the fractions:
\[
x \cdot x^3 = 72 \cdot 18
\]
This simplifies to:
\[
x^4 = 1296
\]
Next, we take the fourth root of both sides:
\[
x = \pm \sqrt[4]{1296}
\]
Now, we need to find \(\sqrt[4]{1296}\). First, find the prime factorization of 1296:
\[
1296 = 36 \times 36 = 6^2 \times 6^2 = (6^2)^2 = 6^4
\]
So,
\[
1296 = 6^4
\]
Therefore,
\[
\sqrt[4]{1296} = 6
\]
Thus, we get:
\[
x = \pm 6
\]
The final answer is:
\[
\boxed{\pm 6}
\]