To evaluate the expression \(\frac{n(2n + 1)}{n - 1}\) for \(n = \frac{2}{3}\), we first substitute \(\frac{2}{3}\) for \(n\).
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Calculate \(2n + 1\): \[ 2n + 1 = 2\left(\frac{2}{3}\right) + 1 = \frac{4}{3} + 1 = \frac{4}{3} + \frac{3}{3} = \frac{7}{3} \]
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Calculate \(n(2n + 1)\): \[ n(2n + 1) = \frac{2}{3} \cdot \frac{7}{3} = \frac{14}{9} \]
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Calculate \(n - 1\): \[ n - 1 = \frac{2}{3} - 1 = \frac{2}{3} - \frac{3}{3} = -\frac{1}{3} \]
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Substitute \(n(2n + 1)\) and \(n - 1\) into the expression: \[ \frac{n(2n + 1)}{n - 1} = \frac{\frac{14}{9}}{-\frac{1}{3}} \]
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Simplify: \[ \frac{14}{9} \div -\frac{1}{3} = \frac{14}{9} \cdot -3 = \frac{14 \cdot -3}{9} = -\frac{42}{9} \]
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Simplify \(-\frac{42}{9}\): \[ -\frac{42}{9} = -\frac{14}{3} \]
Thus, the value of the expression for \(n = \frac{2}{3}\) is \(\boxed{-\frac{14}{3}}\).