Given that the cube root of 27 is 3, what is 2743

?Responses

108
108

4
4

12
12

81

1 answer

To solve for \( 2743 \), we can break it down using the properties of exponents. The number \( 2743 \) can be rewritten as \( (27)^{4/3} \).

Given that \( \sqrt[3]{27} = 3 \), we raise both sides to the power of 4:

\[ (3)^4 = 81 \]

Thus, we can compute \( 2743 \) as follows:

\[ 2743 = (27)^{4/3} = 3^4 = 81 \]

Therefore, the answer is:

81