Question

In a local election, four nominees each received a portion of the votes, as shown in the table.

Nominee Voting Portion
Mr. Douglas 9/50
Mrs. Maury 26%
Mr. Hill 7/20
Mrs. Jackson 0.21
Put the nominees in order of how many votes they received, beginning with the winner.

Mrs. Jackson, Mrs. Maury, Mr. Douglas, Mr. Hill
Mr. Hill, Mrs. Jackson, Mrs. Maury, Mr. Douglas
Mr. Hill, Mrs. Maury, Mrs. Jackson, Mr. Douglas
Mrs. Maury, Mr. Hill, Mrs. Jackson, Mr. Douglas

Answer 1

To compare the portions of votes received by the nominees, we can convert all of them to the same format (decimals).

Let's convert each nominee's voting portion:

1. **Mr. Douglas**: \( \frac{9}{50} = 0.18 \)
2. **Mrs. Maury**: \( 26\% = 0.26 \) (as a decimal)
3. **Mr. Hill**: \( \frac{7}{20} = 0.35 \)
4. **Mrs. Jackson**: \( 0.21 \)

Now we have the following vote portions in decimal format:

- Mr. Douglas: 0.18
- Mrs. Maury: 0.26
- Mr. Hill: 0.35
- Mrs. Jackson: 0.21

Now we can compare the values:

1. Mr. Hill: 0.35
2. Mrs. Maury: 0.26
3. Mrs. Jackson: 0.21
4. Mr. Douglas: 0.18

Putting them in order of votes received from highest to lowest, we get:

1. Mr. Hill
2. Mrs. Maury
3. Mrs. Jackson
4. Mr. Douglas

Thus, the correct order is:

**Mr. Hill, Mrs. Maury, Mrs. Jackson, Mr. Douglas**.