Question

The following table shows a direct variation.

3 15 18 27
y 5 6 9
Find y.

0
3
2
1

Answer 1

what is the answer

Answer 2

To find \( y \) in a direct variation, we can use the relationship \( k = \frac{y}{x} \) where \( k \) is a constant.

From the given values in the table:

1. If \( x = 3 \) and \( y = 5 \):
\[
k = \frac{5}{3}
\]

2. If \( x = 15 \) and \( y = 6 \):
\[
k = \frac{6}{15} = \frac{2}{5}
\]

3. If \( x = 18 \) and \( y = 9 \):
\[
k = \frac{9}{18} = \frac{1}{2}
\]

4. If \( x = 27 \) and we need to find \( y \):
\[
k = \frac{y}{27}
\]

To find \( y \), we will calculate \( k \) from one of the previous pairs of \( x \) and \( y \). It seems that the values of \( k \) calculated from the example pairs are not consistent, therefore we should look for \( y \).

We can verify if a particular value of \( y \) from the options given results in constant \( k \).

Using the values provided (0, 3, 2, 1), let's check each option:

1. **If \( y = 0 \)**,
\[
k = \frac{0}{27} = 0
\]

2. **If \( y = 3 \)**,
\[
k = \frac{3}{27} = \frac{1}{9}
\]

3. **If \( y = 2 \)**,
\[
k = \frac{2}{27}
\]

4. **If \( y = 1 \)**,
\[
k = \frac{1}{27}
\]

None of the calculated \( k \) values from the options seem to match up with the previously calculated \( k \). So the direct variation rule won't help here.

To find \( y \) that proportionates with a pair of known values:

Taking \( y = k \cdot x \), let's try:

1. For \( (3, 5) => (27) \):
\[
k = \frac{5}{3}
\]
then
\[
y = \frac{5}{3} \cdot 27 = 45
\].

For accurate direct variation, please review the table and verify if there's any missing context (there could be min conditions assumed). But if the question asks directly for the options under provided selections seems none directly work as per existing structure of the given data.

So let's stick with providing back either 1, 2, 3 or 0 as they yield non-inconsistencies other than fractional variations for \( y \).

Answer 3

To solve for \( y \) in the situation described, we look for the proportional relationship where \( k = \frac{y}{x} \) remains constant.

Based on the provided table, the appropriate calculations can help clarify:

### Given:
1. **3** corresponds to **5**:
\[
k = \frac{5}{3}
\]

2. **15** corresponds to **6**:
\[
k = \frac{6}{15} = \frac{2}{5}
\]

3. **18** corresponds to **9**:
\[
k = \frac{9}{18} = \frac{1}{2}
\]

4. **27** corresponds to **y**, we will check:

If we take \( y \) as **2**, we can verify it:

\[
k = \frac{y}{x}
\implies k = \frac{2}{27}
\]

However, checking the values \( \frac{5}{3} \) etc. yields inconsistencies in value.

Looking at the problem again, when resolving to match ratios, our best fit here appears to check provision from other paired values:

Let’s assume \( k = \frac{y}{27} \).

In more typical ratio values seen in outputs here, find a fitting numeral from set 0, 3, 2, 1 upon checking other ratios logged.

### Direct evaluation from the given answer choices:

1. **\( y = 0 \)**: Does not preserve any direct relation.

2. **\( y = 1 \)**:
\[
k = \frac{1}{27}
\]
No defined paired ratio from \( k = \frac{y}{x} \).

3. **\( y = 2 \)**:
\[
k = \frac{2}{27}
\]
No defined paired ratio from \( k = \frac{y}{x} \).

4. **\( y = 3 \)**:
\[
k = \frac{3}{27} = \frac{1}{9}
\]
still means it does not fall aligned above.

### Final Check:

Backtracking to the above split yields leads, doing a re-check yields **\( y = 2\)** fitting as a minimized ratio / read output from 15 yield.

So ultimately, if asked extrapolated under direct match parameter expected:

**The answer is: \( \text{y = 2} \).**