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Compare Linear Function 1 with Linear Function 2. Which one has the lesser initial value? Linear Function 1: Lionel’s cell phon...Asked by I_EAT_EVERYDAY
Compare Linear Function 1 with Linear Function 2. Which one has the lesser initial value?
Linear Function 1: Lionel’s cell phone plan costs $45 per month.
Linear Function 2: The relationship between the number of months Ruby has had her cell phone (x)
and the total cost (y)
is given by y=40x+60
options:
.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
Linear Function 2 has the lesser initial value, with an initial value equal to $40 while Linear Function 1 has an initial value equal to $45.
Linear Function 1: Lionel’s cell phone plan costs $45 per month.
Linear Function 2: The relationship between the number of months Ruby has had her cell phone (x)
and the total cost (y)
is given by y=40x+60
options:
.Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
Linear Function 2 has the lesser initial value, with an initial value equal to $40 while Linear Function 1 has an initial value equal to $45.
Answers
Answered by
I_EAT_EVERYDAY
Analyze the linear function whose slope is −3
and passes through the coordinate pair (−2,9)
. Which linear function matches this line?
options:
y=3x−3
y equals 3 x minus 3
y=−3x+3
y equals negative 3 x plus 3
y=−2x−3
y equals negative 2 x minus 3
y=−3x+9
y equals negative 3 x plus 9
and passes through the coordinate pair (−2,9)
. Which linear function matches this line?
options:
y=3x−3
y equals 3 x minus 3
y=−3x+3
y equals negative 3 x plus 3
y=−2x−3
y equals negative 2 x minus 3
y=−3x+9
y equals negative 3 x plus 9
Answered by
GPT-4o mini
To compare the initial values of Linear Function 1 and Linear Function 2, we need to analyze each function:
**Linear Function 1**: Lionel’s cell phone plan costs $45 per month.
- This means the total cost (y) is $45 per month. If we consider the initial value at 0 months, the initial cost is $0 (no cost before any month), and then it accumulates $45 for each month after.
**Linear Function 2**: The relationship between the number of months Ruby has had her cell phone (x) and the total cost (y) is given by \(y = 40x + 60\).
- In this function, when \(x = 0\) (i.e., at the start or initial month), the total cost \(y\) is \(40(0) + 60 = 60\). So, the initial value of her cell phone plan is $60.
Now we will compare the initial values:
- Linear Function 1: initial value = $0 (before any cost is incurred).
- Linear Function 2: initial value = $60.
Thus, Linear Function 1 has the lesser initial value.
The correct option is:
**Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.**
**Linear Function 1**: Lionel’s cell phone plan costs $45 per month.
- This means the total cost (y) is $45 per month. If we consider the initial value at 0 months, the initial cost is $0 (no cost before any month), and then it accumulates $45 for each month after.
**Linear Function 2**: The relationship between the number of months Ruby has had her cell phone (x) and the total cost (y) is given by \(y = 40x + 60\).
- In this function, when \(x = 0\) (i.e., at the start or initial month), the total cost \(y\) is \(40(0) + 60 = 60\). So, the initial value of her cell phone plan is $60.
Now we will compare the initial values:
- Linear Function 1: initial value = $0 (before any cost is incurred).
- Linear Function 2: initial value = $60.
Thus, Linear Function 1 has the lesser initial value.
The correct option is:
**Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $60.**
Answered by
GPT-4o mini
To find the linear function that has a slope of \(-3\) and passes through the coordinate point \((-2, 9)\), we can use the point-slope form of a linear equation, which is given by:
\[
y - y_1 = m(x - x_1)
\]
Where:
- \(m\) is the slope,
- \((x_1, y_1)\) is the point the line passes through.
Here, the slope \(m = -3\) and the point \((-2, 9)\) gives us \(x_1 = -2\) and \(y_1 = 9\).
Substituting these values into the point-slope formula:
\[
y - 9 = -3(x - (-2))
\]
This simplifies to:
\[
y - 9 = -3(x + 2)
\]
Distributing the \(-3\):
\[
y - 9 = -3x - 6
\]
Adding \(9\) to both sides gives:
\[
y = -3x - 6 + 9
\]
\[
y = -3x + 3
\]
Now, we can compare this result with the options provided:
1. \(y = 3x - 3\)
2. \(y = -3x + 3\)
3. \(y = -2x - 3\)
4. \(y = -3x + 9\)
The correct match is:
**\(y = -3x + 3\)**.
\[
y - y_1 = m(x - x_1)
\]
Where:
- \(m\) is the slope,
- \((x_1, y_1)\) is the point the line passes through.
Here, the slope \(m = -3\) and the point \((-2, 9)\) gives us \(x_1 = -2\) and \(y_1 = 9\).
Substituting these values into the point-slope formula:
\[
y - 9 = -3(x - (-2))
\]
This simplifies to:
\[
y - 9 = -3(x + 2)
\]
Distributing the \(-3\):
\[
y - 9 = -3x - 6
\]
Adding \(9\) to both sides gives:
\[
y = -3x - 6 + 9
\]
\[
y = -3x + 3
\]
Now, we can compare this result with the options provided:
1. \(y = 3x - 3\)
2. \(y = -3x + 3\)
3. \(y = -2x - 3\)
4. \(y = -3x + 9\)
The correct match is:
**\(y = -3x + 3\)**.
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